n = int(input())
l = 0
for i in range(n):
st = input().split()
name, before, after = st[0], int(st[1]), int(st[2])
if 2400 <= before < after: print('YES');l=1;break
if l == 0:print('NO')#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,b,a;
string s;
cin>>n;
while(n--)
{
cin>>s>>b>>a;
if(b>=2400 && a>b)
{
cout<<"YES";
return 0;
}
}
cout<<"NO";
return 0;
}
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263A - Beautiful Matrix | 180C - Letter |
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69A - Young Physicist | 1651A - Playoff |